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[2-2(sqrt3i)]^4 =r(cos(theta)+isin(theta)) where 0

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  • [2-2(sqrt3i)]^4 =r(cos(theta)+isin(theta)) where 0


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[2-2(sqrt3i)]^4 =r(cos(theta)+isin ... 0
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Positive: 34 %
[2-2(sqrt3i)]^4 =r(cos(theta)+isin(theta)) where 0
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Positive: 31 %

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Positive: 10 %