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[2( \cos(135^\circ)+ i \sin(135^\circ))]^4 = r(\cos(\theta^\circ)+ i \sin(\theta^\circ)) where 0

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  • [2( \cos(135^\circ)+ i \sin(135^\circ))]^4 = r(\cos(\theta^\circ)+ i \sin(\theta^\circ)) where 0


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... (135^\circ)+ i \sin(135^\circ))]^4 = r(\cos(\theta^\circ)+ i \sin(\theta^\circ)) where 0
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Positive: 23 %
... (135^\circ))]^4 = r(\cos(\theta^\circ)+ i \sin(\theta^\circ)) where 0
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Positive: 20 %
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