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2Al2O3(s)→4Al(s)+3O2(g), ΔH = +801 kcal/mol....How many kilocalories are required to produce 1.88 mol of aluminum?

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  • 2Al2O3(s)→4Al(s)+3O2(g), ΔH = +801 kcal/mol....How many kilocalories are required to produce 1.88 mol of aluminum?


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... →4Al(s)+3O2(g), ΔH = +801 kcal/mol....How many kilocalories are required to produce 1.88 mol of aluminum? ... 4Al(s) 3O2(g) 2Al2O3(s)How many grams ...
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Positive: 67 %
... (s)+3O2(g), ΔH = +801 kcal/mol....How many kilocalories are required to produce 1.88 mol of ... to aluminum 2al2o3 s 4al s 3o2 g h 801 kcal mol. ...
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Positive: 64 %

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