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2Al2O3(s)→4Al(s)+3O2(g), ΔH = +801 kcal/mol....How many kilocalories are required to produce 1.88 mol of aluminum?

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  • 2Al2O3(s)→4Al(s)+3O2(g), ΔH = +801 kcal/mol....How many kilocalories are required to produce 1.88 mol of aluminum?


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