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{2x+4y+z=1;x-2y-3z=2;x+y-z=-1?

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  • {2x+4y+z=1;x-2y-3z=2;x+y-z=-1?


Answers

x+y+z=-1 2x+4y+z=1 x+2y-3z=-3 (p^4q^8)/(p^3q^6) 7/12x-1/4=5 (-66,92)to(64,-94) 1*(-2)+2; x=7^548-7^537; x=5^7393-5^7390; 0=x^4+x^3+7x^2+93x-18; 4v^2+v-3=0;
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Positive: 64 %
That's a system of 3 equations on 3 variables. I suppose you're asking to solve it; please say it so next time. 2x + 4y + z = 1 x - 2y - 3z = 2 x + y - z ...
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Positive: 61 %

More resources

... #!2x+4y+z=1# ## !x−2y−3z=2# # !x+y−z=−1# # # # # # # # # # # # # # # # # # # b)#!x+2y−7z=−4#!2x+y+z=13#!3x+9y−36z=−33
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Positive: 64 %
HOLIDAY HOMEWORK (2015-16) ENGLISH - XII ... i 3x + 4y + 7z = 14, 2x - y + 3z = 4, x + 2y ... iv. x + y + z =1,x - 2y + 3z =2, x - 3y + 5z =3 v. x - y + z ...
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Positive: 59 %
x y z 1 x 2y 3z 2 x 4y 5z 4 ­ ... 2x 3y z 1 ...
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Positive: 45 %
x + y + z = 1. x – 2y + 3z = 2 ...
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Positive: 22 %

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