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3 Pb(NO3)2 + 2 Na3PO4 → 1 Pb3(PO4)2 +6 NaNO3 Number of moles of Pb3(PO4)2 that can be formed from each starting reagent is: from Pb(NO3)2=?

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  • 3 Pb(NO3)2 + 2 Na3PO4 → 1 Pb3(PO4)2 +6 NaNO3 Number of moles of Pb3(PO4)2 that can be formed from each starting reagent is: from Pb(NO3)2=?


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