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' a⁴/(a - b)(a - c) + b⁴/(b - c)(b - a) + c⁴/(c - a)(c - b) =    .?

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  • ' a⁴/(a - b)(a - c) + b⁴/(b - c)(b - a) + c⁴/(c - a)(c - b) =    .?


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' a⁴/(a - b)(a - c) + b⁴/(b - c)(b ... { c⁴ / [(a - c)(b - c)] } The common denominator is: (a - b).(a - c).(b - c) = [a⁴.(b - c) - b⁴.(a - c ...
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Positive: 31 %
Here is an alternative solution to Kb's: WLOG, assume a ≤ b ≤ c. Apply the rearrangement inequality to the 4 sets {a, b, c}, {a, b, c}, {b, c, a}, {c ...
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Positive: 28 %

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a,b,c为正整数,求证a八次+b八次+c八次≥a立方b立方c平方+a ... (c²+a²)/2,a²b²≤(a²+b²)/2】 ≤a⁴(b⁴+c⁴)/2 +b⁴(c⁴+a⁴ ...
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Positive: 31 %
(a+b+c)⁴的各项 ... 含有a⁴类的系数可见为1,含有 ... 所以(a+b+c)⁴=a⁴+b⁴+c⁴+4a³b+4a³c+4b³a+4b³c+4c³a+4c³b+12a²bc ...
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Positive: 26 %
解: a²+b²+c²=(a+b+c ... (2-a) =6-2ab+abc-2ac+abc-2bc+abc =6-2(ab+bc+ca)+3abc =6-1+3abc =5+3abc=4 abc=-1/3 a⁴+b⁴+c⁴ =(a³+b³+c³)(a+b+c) ...
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Positive: 12 %
SAS代码关于预测求帮忙运行 ; 10万元到内蒙古草原怎么养活自己? 哪位大神对远程软件RadminVi... 桑拿桑拿桑拿桑拿 ...
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Positive: 10 %

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