Find right answers right now! Complex: evaluate e^(1+i) log(1+i) (1+i)^(1+i) sin( pi/4 +I)? More questions about Science & Mathematics
Read more

Positive: 95 %

Complex: evaluate e^(1+i) log(1+i) (1+i)^(1+i) sin( pi/4 +I)? Find answers now! No. 1 Questions & Answers Place. More questions about Science & Mathematics
Read more

Positive: 92 %

More resources

Review of Trigonometric, Logarithmic, and Exponential Functions ... displaystyle \frac{1}{\sin ... log_b 1=0 & \longleftrightarrow & b^0=1 ...
Read more

Positive: 95 %

Evaluate complex value and domain of analytic function ... Evaluate the following if they exist: a) sin(3Logi) b) (1 ... (1/6)Log(2)- (pi/4)}+ ...
Read more

Positive: 90 %

Maxima 5.38.1 Manual: 10. Mathematical Functions ... the polylogarithm simplifies to - log (1 ... 2 3 (%i3) [sin (%pi/4), sin (%pi/5 ...
Read more

Positive: 76 %

Sine; Basic features; Parity: odd: Domain (− ∞, ∞) a: Codomain [−1,1] a: Period ... Specific features; Root: k π: Critical point: k π − π / 2 ...
Read more

Positive: 53 %

Show more results

Evaluate the following: $(1-i)^ ... case $\log(1-i) = \ln \sqrt 2 - \dfrac{i\pi}4 + 2\pi i k$ for some ... 2}\ln\left(2\right)\right) + {\rm i}\sin\left({1 ...
Read more

Positive: 95 %

1 Review of complex numbers 1.1 Complex numbers: ... 2 sin 1 sin 2) + i(cos 1 sin 2 + cos ... 1.3 Complex numbers: ...
Read more

Positive: 94 %

EULER’S FORMULA FOR COMPLEX EXPONENTIALS ... = icos t¡ sin t since i2 = ¡1 d dt ... and try to get back to the arctan you know and love by using the ...
Read more

Positive: 89 %

... Log of Complex Number Does the log of a complex ... since Cos[y]^2+Sin[y]^2 = 1 ... 1+I. Then Arg[w] = Pi/4, ...
Read more

Positive: 82 %

- 2 sin(2z) - i sin(1 ... = i, so z^2 = 1 + i, so z = (1+i)^{1/2} = (sqrt(2) exp(i pi/4))^{1/2 ... is a branch of log(2z-1) everywhere in the complex plane ...
Read more

Positive: 72 %

Computing the integral of $\log(\sin x)$ ... {\pi/4}\log(\sin x)dx=-\frac{\pi}{4}\log 2-\sum_{k\ge 1}\frac{\sin(\pi ... Is there other methods to evaluate ...
Read more

Positive: 59 %

SOLUTIONS TO HOMEWORK ASSIGNMENT # 7 1. ... k=1 (−1)k+1 1 k (2z)k = π + Log(1 + 2z). ... Evaluate Z π −π 1 1+sin2 ...
Read more

Positive: 43 %

... pi/4) and e^(pi/6i)=cos(pi/6)+isin(pi/6) Hence, e^(pi/4i)-e^(pi/6i)=cos(pi/4)+isin(pi/4)-cos(pi/6)-isin(pi/6) = cos(pi/4)-cos(pi/6)+i(sin(pi/4)-sin(pi ...
Read more

Positive: 24 %

Examining the question at hand, [math]f(t) = \frac{\sin t} {t}[/math] and introduce a variable [math]s = 1[/math] into the exponential function such that ...
Read more

Positive: 2 %

... As cos(pi/4)=cos((7pi)/4)=1/sqrt2, sin(pi/4)=1/sqrt2 ... 7 pi)/4 i)# using trigonometric functions? ... form in complex form #3/2 ...
Read more

... * pi) 4.44288293815837 ... numerical evaluation cannot tell an expression that is exactly zero ... . evalf 1.64493406684823 >>> Sum (1 / k-log (1 + 1 ...
Read more

Positive: 10 %

and the corresponding Taylor series for log(x) at a = 1 is ... to its Taylor series for all x in the complex ... an accurate approximation of sin(x) ...
Read more

Read more

95 %