# Consider the equation x^2 + 2x + k= 5, where k is a constant. If 3 is a solution of the equation, then the second solution is:?

• Consider the equation x^2 + 2x + k= 5, where k is a constant. If 3 is a solution of the equation, then the second solution is:?

... solutions of a linear,homogeneous second-order diﬀerential equation then the ... solution of: d2y dx2 +3 d ... (k +5)=0 so that k ...
Positive: 79 %
This section will deal with solving the types of first and second order differential equations ... constant e k. We now have a solution ... equation. s + 5 ...
Positive: 76 %

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One root of equation [math]x^4 - 5 x^3 + a x^2 ... (Equality is symmetric, i.e., if a = b, then b = a) y = ‒x/2 (this equation ... x^2 + (2x-k)^2 = 5 ...
Positive: 79 %
k is a negative constant. 5) ... lny=2x2+c When x=2, y=1 (given) ! ln1=8+c 0=8+c ... As time increases without bound then 3.2 t e!
Positive: 74 %
1. Solving Differential Equations ... (x^2 - 3)dx` Then the answer is the same as before, ... we obtained a general solution (involving a constant, K).