Graphing log graph of y = log3(x- 2)-3. Graphing log graph of y = log3(x- 2)-3. Skip navigation Upload. Sign in. ... Graph y=log4(x) - Duration ...
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Positive: 85 %

You can put this solution on YOUR website! I assume you mean and not ... The function is only defined for x>-2.
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Positive: 82 %

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... the answer I am getting is x=-3/2+1/6 =sqrt 409 I need ... +log3(x+1)=log[3\cdot 3\cdot (x+2)\cdot (x+1)] \] \[\large =log[9\cdot (x^2+3x+2 ...
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How do you solve this? 5 = log3(x^2 + 18)5 = log 10^5 --> log 10^5 = log 3 (x^2 +18). take both log out 10^5 = 3 (x^2 +18) and then solve as us...
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Positive: 66 %

Pure Math 30: Explained! www.puremath30.com 121 Logarithms Lesson 3 ... =log4+log3 log4+log3 x= 2log4 -log5 x = 2.14 Example 4: Example 2: 2=3x+3 2x-1 33 3
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Positive: 43 %

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Given: f(x) = log3 (x + 1), ... prove that the x-coordinates of the endpoints of a focal chord of x^2=4py are x=2p(m±√(m^2 1), where m is ...
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Positive: 85 %

... log3 (x) +2. http://www ... Pre-Calculus - Finding the domain asymptote and x ... Find the vertical and horizontal asymptotes f(x)=4/(x-2)^3 ...
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Positive: 84 %

Die Logarithmusfunktion ist die Umkehrfunktion der Exponentialfunktion mit f(x)=a x (a>0). D.h., ... (x)=x 2 als Nullpunktgerade mit der Steigung 2 dar.
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Positive: 79 %

The equation `log_2 x - log_ 4 x = 2` has to be solved for x. ... For the function f(x)=x^2-5 find the domain and range. More Math Questions.
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Positive: 72 %

Given the function f(x) = log3(x + 4), find the value of f−1(3).? Find answers now! No. 1 Questions & Answers Place. More questions about Education ...
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Positive: 62 %

You can put this solution on YOUR website! To graph this, use the well-known formula In this case, . Are you allowed to use a graphing calculator?
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Positive: 49 %

... (log3 x)^2=log3 (x^2) + 3 ?' and find homework help for other Math questions at ... Given f(x) and g(x), please find (fog)(X) and (gof)(x) f(x) = 2x ...
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Positive: 33 %

Chapter 8 Exponential and Logarithmic Functions. Example 8.1.4. f(x)=3x+1 − 2 has the same graph as y = 3x, but is shifted one unit ..... Use the graphs ...
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85 %