# Find the distance traveled from t=1 to t=5 seconds, for a particle whose velocity is given by v(t)=t+ln(t)?

• Find the distance traveled from t=1 to t=5 seconds, for a particle whose velocity is given by v(t)=t+ln(t)?

Find the distance traveled from t=1 to t=5 seconds, for a particle whose velocity is given by v(t)=t+ln ... Find the distance traveled from t=1 to t=5 ...
Positive: 48 %
In order to find the distance traveled by a particle when given the ... >0 its velocity is given by v(t) = cos(t+t^(1 ... Find the total distance traveled ...
Positive: 45 %

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... for a particle whose velocity is given by v(t) ... At time t =1, the velocity of the particle is v(1) ... distance traveled by the particle from 3 2 t ...
Positive: 48 %
... the total distance traveled by the particle from t = 0 to t = 5 ... velocity at time t is given by v ... v(t). (b) Find the total distance traveled ...
Positive: 43 %
... the velocity v1 at time t1 is not ... lasting 3 seconds is given by the distance traveled ... at t = 5. Moreover the traveled distance is ...