FIND THE ANSWERS

Given 2(cos(t))^2 - cos(t) -1 = 0, what are the intervals between [0,2pi]?

Answer this question

Do you know the correct answer? Make money answering questions! Join now.
  • Given 2(cos(t))^2 - cos(t) -1 = 0, what are the intervals between [0,2pi]?


Answers

Given 2(cos(t))^2 - cos(t) -1 = 0, ... Given 2(cos(t))^2 - cos(t) -1 = 0, what are the intervals between [0,2pi]? You mean the solutions to the problem ...
Read more
Positive: 53 %
Find right answers right now! Given 2(cos(t))^2 - cos(t) -1 = 0, what are the intervals between [0,2pi]? ... Given 2(cos(t))^2 - cos(t) -1 = 0, what are ...
Read more
Positive: 50 %

More resources

... given below, determine the intervals on which f(x) ... > 0. That is either between 2 and 8, ... (0 2pi) but 7pi/6 is in the ...
Read more
Positive: 53 %
y=0.2(x-1) ^3-3A.)Graphb).Give ... the graph of t. Given the following function, f(x)=-x^2 -8x ... =0.2x^3-0.2x^2-5x-4. 11 Find the intervals on which the ...
Read more
Positive: 48 %
Increasing/decreasing intervals? extrema? inflection points? HELP? f(x) ... = cos(x)-x/2 at 0????? ... (0 2pi) but 7pi/6 is in the ...
Read more
Positive: 34 %
2. y = sin x + cos x [0,2pi] 0 0. Edit. Report. ... wouldn't those be the intervals where the ... and then rises again between 3 pi/2 and 2 pi. That means ...
Read more
Positive: 11 %

Show more results