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Given that CaO(s) + H2O(l) → Ca(OH)2(s), delta H = –64.8 kJ/mol, how many grams of CaO must react in order to liberate 525 kJ of heat?

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  • Given that CaO(s) + H2O(l) → Ca(OH)2(s), delta H = –64.8 kJ/mol, how many grams of CaO must react in order to liberate 525 kJ of heat?


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Answer to Given that CaO(s) + H2O(l) --> Ca(OH)2(s), delta Hrxn = -64.8 kJ/mol, how many grams of CaO must react ... react in order to liberate 525 kJ of ...
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... (l) → Ca(OH)2(s), delta H = –64.8 kJ/mol, how many grams of CaO must react in order to liberate 525 kJ ... 64.8 kJ/mol, how many grams of CaO must ...
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Positive: 47 %

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