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# How do I evaluate the integral 4cos(πx/2) dx from 0 to 1?

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• How do I evaluate the integral 4cos(πx/2) dx from 0 to 1?

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Hello, ₁ ∫ 4cos[(πx)/2] dx = ⁰ let's figure out the antiderivative, first: ∫ 4cos[(πx)/2] dx = let: (πx)/2 = u (π/2)x = u x = [1/(π/2)] u ...
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Positive: 40 %
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Positive: 37 %

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Positive: 35 %
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