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How do I explain that sin(1/x) is not continuous at x=0?

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  • How do I explain that sin(1/x) is not continuous at x=0?


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... =\sin(1/x)$ is not uniformly continuous? ... How do I go about proving $f(x)=\sin(1/x) ... I really appreciate the time you took to explain the way of ...
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Positive: 37 %
... that function isn't continuous at x = 0. It's not even ... Sin(1/x) -Cos(1/x)/x At x =0 or rather we ... x\right)}{\sin\left(x\right)}[/math] How do I ...
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Positive: 34 %

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Uniform Continuity 19.4 (a) We will ... By part (a), it is clear that f(x) = 1/x2 is not uniformly continuous on ... x −0 = lim x→0 x2 sin 1 x −0 x = lim
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Positive: 37 %
Continuous Functions. A function is continuous when its graph is a single unbroken curve ... = 1/(x-1) for x>1: NOT continuous : ... At x=0 it has a very ...
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Positive: 32 %
C. CONTINUITY AND DISCONTINUITY 1. ... (not even as ±∞). Though sin(1/x) ... x > 0, −1, x < 0 does not have a continuous derivative f ...
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Positive: 18 %
Limit and Continuity of Trigonometric Functions ... is continuous everywhere except at cos(x) = 0 which gives ... lim x → 0 x 2 sin 2 (1/x) = 0
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Positive: 10 %

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