# How is the second one wrong if it is just the integral of the first part. For the second I put x+3/2x^3+243/40x^5?

• How is the second one wrong if it is just the integral of the first part. For the second I put x+3/2x^3+243/40x^5?

How is the second one wrong if it is just the integral of the first part. For the second I put x+3/2x^3 ... part. For the second I put x+3/2x^3+243/40x^5?
Positive: 50 %
Calculus 2 Integration ... Is the integral one of our standard forms? If so, do it. Question 2. ... In the first column put x 5.
Positive: 47 %

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Hughes-Hallett, Calculus 6e ... has the same first and second derivatives as y = ln x at x ... for a ≤ x ≤ b. This proves the first part of the ...
Positive: 50 %
... however I a struggling to determine how r is formed in the first part of the second ... just ONE method either using ... (x^2+y^2)dydx ⌡0⌡0 ...
Positive: 45 %
C2 Algebra Answers . 1. M1 A1. A1. M1 A1 5 [5] 2. (a) Finding f ( 2), and obtaining 16 – 32 + 10 + 6 = 0 M1, A1 2 . Or. uses division and obtains 2x2 ...