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How many grams of zinc can react with 130.0 mL of a 1.25 M HCl solution according to the equation below Zn(s)+2HCl(aq)-> ZnCl2(aq)+H2(g) ?

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  • How many grams of zinc can react with 130.0 mL of a 1.25 M HCl solution according to the equation below Zn(s)+2HCl(aq)-> ZnCl2(aq)+H2(g) ?


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... zinc can react with 130.0 mL of a 1.25 M HCl solution according to the equation below Zn(s)+2HCl(aq)-> ZnCl2(aq)+H2 ... 130.0 mL of a 1.25 M HCl ...
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Positive: 42 %
1. 25. mL of the 3.51 M stock solution is diluted to 150. mL to make soln2 ... (aq) + H2(g) 2. According to the equation above, ... (s) + HCl(aq) → AlCl3 ...
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Positive: 39 %

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Zn(s) + 2HCl(aq)->ZnCl2(aq) + H2(g) I'm ... H2. What volume, in ml of a 1.25 M solution would ... 1.8 mol Zn and 7.3 mol HCl react according to the ...
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Positive: 42 %
Chem Problems. by deblasijanine. on Oct 07, 2014. Report Category: Documents. Download: 2 Comment: 0. 437. views. Comments. Description. Download Chem ...
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Positive: 37 %
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Positive: 23 %
... (s) + 2HCl(aq) → MgCl2(aq) + H2(g) ... dioxide and they react according to the equation: 2H2S(g) ... dissolved in 500 mL of solution c 2.048 M.5 mol ...
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Positive: 10 %

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