FIND THE ANSWERS

# How much solute is required to prepare A. Gram of KMnO4 for 20.0 mL of 0.0100 M KMnO4. B. Moles of NaOH for 1.25 L of 0.0235 M NaOH?

### Answer this question

• How much solute is required to prepare A. Gram of KMnO4 for 20.0 mL of 0.0100 M KMnO4. B. Moles of NaOH for 1.25 L of 0.0235 M NaOH?

## Answers

How much solute is required to prepare A. Gram of KMnO4 for 20.0 mL of 0.0100 M KMnO4. B. Moles of NaOH for 1.25 L ... B. Moles of NaOH for 1.25 L of 0 ...
Read more
Positive: 57 %
1.0 dm33 = 1000 cm = 1.000 L. CALCULATIONS INVOLVING SOLUTIONS ... of NaOH = 40.0 g, so 0.50 mol of NaOH = 20.0 g. ... g 200 mL = 0.200 L Number of moles ...
Read more
Positive: 54 %

### More resources

The density of seawater is 1.025 g / mL. (c) How much time is required for ... reacted with 20.0 mL of 0.410 M NaOH. ... aq) + 4H2O(l) How many moles ...
Read more
Positive: 57 %
(b) How many grams of Cr 2 O 3 are required? ... M (c) moles of solute in 145.6 L of 0.743 M ... are needed to react with 43.81 mL of 0.285 M NaOH? NaH 2 ...
Read more
Positive: 52 %
... = score for question 4 (Points earned for question 5)(1.25) ... B: You Have One Semester to Prepare ... mL of a 0.20 M KBr solution. How many moles ...
Read more
Positive: 38 %
b) it is one gram of solute per million grams ... Calculate how much glucose you have in 20.0 mL of the ... 0.890 moles + [(x) (3.88 L)] = 5.73 molesx = 1 ...
Read more
Positive: 15 %

Show more results

Anonymous50867
Login to your account
Create new account

Discover Questions