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If you start with 10.0 moles of C3H8 (propane) and 10.0 moles of O2, what is the limiting reactant. C3H8(g) + 5O2(g) ® 3CO2(g) + 4H2O(g)?

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  • If you start with 10.0 moles of C3H8 (propane) and 10.0 moles of O2, what is the limiting reactant. C3H8(g) + 5O2(g) ® 3CO2(g) + 4H2O(g)?


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