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Integrate (9-x^2)^1/2?

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x=3sino dx=3coso do and x/3=sino so Integrate x^2/(9-x^2)^1/2 dx =Integrate (x^2/3coso) 3coso do =Integrate x^2 do =x^3/3 + C Then...I don't know how to do
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... du which is immediate: (a^2 / 2) (u + (1/2) sin 2u) = (a^2 ... How do I integrate [math]\int_1^2\int_1^2 ... (9-x^2)^\frac{1}{2}[/math] with ...
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