# Integrate of 1 / (u+1) du = ln (u + 1) + C or do I still need to use some substitution like do I still need to integrate?

• Integrate of 1 / (u+1) du = ln (u + 1) + C or do I still need to use some substitution like do I still need to integrate?

Integrate of 1 / (u+1) du = ln (u + 1) + C or do I still need to use some substitution like do I still need to integrate? Find answers now! No. 1 Questions ...
Positive: 67 %
Find right answers right now! Integrate of 1 / (u+1) du = ln (u + 1) + C or do I still need to use some substitution like do I still need to integrate?
Positive: 64 %

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1 Integration by Substitution ... tanxdx = lnjcosxj+C = ln 1 jsecxj +C = ln1 ... we use the substitution u = x so that du = dx, we obtain Z a a f (x) ...
Positive: 67 %
I don't understand WHY the integral of 1/(xlnx) is ln(lnx) ... you use substitution: Let u = ln(x) du = (1/x) dx. ... What to do when you need some space?
Positive: 62 %
$$\int {2x\over (x-1)^2}\cdot dx$$ What I have... current community. blog chat. Mathematics ... How to integrate this function with ln and u substitution?