Lim as x->pi/4 (sec^2x-2tgx)/(1+cos4x)? ... (2x)+cos^2(2x)-sin^2(2x ... 2cos^2(2x)*(2sin2x-1)=0; cos^2(2x)=0; 1/2(1+cos4x)=0; Cos4x=-1; x=pi/4+pik/2; ...
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Positive: 78 %

No. 1 Questions & Answers Place. ... Lim as x->pi/4 (sec^2x-2tgx)/(1+cos4x)? Are there any websites where you can ask a physicist a question for free? ...
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78 %