Prove the following Boolean Equality. (A)(B) + (~A)(B) + (A)(~B) + (~(AB)) = 1 Thanks?

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Boolean Algebra A + 0 = A A + A’ = 1 ... A + AB = A.1 + A.B = A. (1 + B) = A. 1 = A . ... (Proof for NAND gates) Any boolean function
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82 %