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Re(1- 2/1-i) and Im(1- 3/i) With steps please! Thank you.?

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  • Re(1- 2/1-i) and Im(1- 3/i) With steps please! Thank you.?


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Re(1- 2/1-i) I am assuming that it is re [1 - (2/(1-i)] multiply the fraction top and bottom by the complex conjugate. re [1 - (2 + 2i)/2] re [1 - 1 + i ...
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