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Solve the equation \sin(4x)+\sin(x) = 0 for values of x in the interval 0 < x < 2\pi. x=?

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  • Solve the equation \sin(4x)+\sin(x) = 0 for values of x in the interval 0 < x < 2\pi. x=?


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Rating is available when the video has been rented. Solve 2 Sin2(x) + Sin (x) =0, 0≤x≤360
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Positive: 22 %
sin x cos x on the interval /4 x 5x/4. Example 2. Solve the equation ... sin x or cos x take the value 0. ... equation sin x ∙ cos x = 0 on the interval ...
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Positive: 19 %

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Solve the equation sin(x) = 0. ... A valid value of k for 0 < x < 2*pi is 1. ... syms x a solve(x^4 + x^3 + a == 0, x) ans = root ...
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Positive: 22 %
... please help me solve sin(x) = sin(2x) interval [0,2pi] ... you could plug in n = 1 into any of the three equations below x = pi*n or x = pi/3 + 2pi*n ...
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Positive: 17 %
How do you solve the equation [math]\sin 2x + \sin 4x ... then what is the value of [math]\cos^{12} x + 3 ... Can anyone solve this problem: lim (x>0) sin ...
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Positive: 3 %
find all solutions to the equation in (0, 2pi) sin ... so 4x = 0 + n pi now solve for x. ... through various values gives until > 2pi = 4pi/2 gives. x ...
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Positive: 10 %

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