# The gradient of the curve C is given by dy/dx= (2x-1)^2. Show that there is no point on C at which the tangent is parallel to the line y=-2x?

• The gradient of the curve C is given by dy/dx= (2x-1)^2. Show that there is no point on C at which the tangent is parallel to the line y=-2x?

How do I determine the equation of the tangent to ... the tangent line of the curve [math]xy^3+2y-2x=1 ... the given curve at point (‒1, ‒3) and 2.) ...
Positive: 67 %
... dy / dx = 2×1 = 2. So 'm' = 2. The tangent line is given by: ... and the gradient, m = dy/dx = 2. ... 2 × 1) so y = 2x - 1.
Positive: 64 %

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