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Use Newton’s method with x-1=0.57 to find the solution of x^3-x-1=0. Correct to six decimal places (list x-34 x-35 x-36 x-37)?

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  • Use Newton’s method with x-1=0.57 to find the solution of x^3-x-1=0. Correct to six decimal places (list x-34 x-35 x-36 x-37)?


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