# Where is the vector function here discontinuous? r(t)=((t^2-3t+2)/(t-1)^2, (t^2-4)/(t+2), ln(2^t)). Please explain!?

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• Where is the vector function here discontinuous? r(t)=((t^2-3t+2)/(t-1)^2, (t^2-4)/(t+2), ln(2^t)). Please explain!?

as a function of r: F(r) = Gm 1 m 2 r ... t = 1, and at time t = 2. (d) Explain the diﬀerence between the values found in part (c) ... 2 t 2 +4 when t is ...
Positive: 85 %
The position of a moving particle is given by the position function. f(t) = -7t - t 2 - 0.2t 3 ... Explain how you got the answer please. ... r(t) = < 2+ln ...
Positive: 82 %

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... (tx)2 = 100t 2 x 2 = t 2 f (x) (b) P (tx) = (tx)1/2 = t 1/2 x 1/2 ... e − 1/e. 2 can be that of a cubic function. (a) 41 t 4 + t 2 ... (1.5 t 2.5 r 2 ...
Positive: 85 %
Fundamentals of Electrical Engineering I by danielraque in Types > Instruction manuals ... Welcome to Scribd! Start your free trial and access books ...
Positive: 80 %
Share Calculus 10e. ... in radians) r s u 1 2 h r V = pr2 ... nxyn−1 ∓ yn TABLE OF INTEGRALS BASIC FUNCTIONS 1. un du = un+1 n + 1 + C 2. du u = ln |u ...