# Write an equation of the tangent line to the graph y=f(x) f(x)=(2x^2+3x-2) (-4x+1) at x=0?

• Write an equation of the tangent line to the graph y=f(x) f(x)=(2x^2+3x-2) (-4x+1) at x=0?

Write an equation of the tangent line to the graph of y = f(x) at the point on the graph where x has the indicated value. f(x) = 2x^2-10/-3x-2, x =0 ...
Positive: 92 %
For #f(x)=x^2 + 2/x# at # x=3#, we get #y = f(3) = 9+2/3 = 29/3# The slope of the tangent line is given by #f'(x)# (I will assume that you know the rules ...
Positive: 89 %

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Thenormal tof atx0 is the line passing through(x0,f ... to the tangent.This has equation y−f(x0) = −1 dy dx ... (x) =0 when 2x2 −8x+6=0,i.e.x =1 or 3 ...
Positive: 92 %
How to Find the Equation of the Tangent Line to a Graph ... of tangent line to a given curve f(x) is y = f ... the equation of the tangent line that ...
Positive: 87 %
There's no single normal to the curve. Instead you have look at the normal at a point [math]x_0[/math], whose equation would be [math]y = -e^{-x_0}*x + 1 ...