# X^2+y^2+z^2=1 x,y,z are positive real numbers. show that xyz^2+xy^2z+x^2yz is less than or equal to 1/3?

• X^2+y^2+z^2=1 x,y,z are positive real numbers. show that xyz^2+xy^2z+x^2yz is less than or equal to 1/3?

X^2+y^2+z^2=1 x,y,z are positive real numbers. show that xyz^2+xy^2z+x^2yz is less than or equal to 1/3? Find answers now! No. 1 Questions & Answers Place.
Positive: 82 %
X^2 + y^2 + z^2 = 1 x,y,z belongs real numbers xyz^2 + xy^2z + x^2yz is less than or eaual to 1/3? ... X^2 + y^2 + z^2 = 1 x,y,z belongs real numbers xyz^2 ...
Positive: 79 %

### More resources

... ^2\cap(y,z)^2\$ but (since \$J=(xy,xz,yz)\$ so \$J^2\$ has no elements of degree less than ... x^2yz^2+(25/2)xy^2z ... x^2*z^2+39/8*x*y*z^2-2*y^2*z^2-1 ...
Positive: 82 %
... (y-2)/36; P:=[1/2, -2/3]; Eval(F, P); -5/162 ----- Eval([x+y,x-y],[2,1]); [3 , 1 ... less than or equal ... x,y,z]; I := Ideal(x^2 ...
Positive: 77 %
Numbers; 3.3. Strings; 3.4. Lists; 3.5. Records; 3.6. Vectors; 3.7. Matrices; 3.8. Rings; 3.9. Polynomials; 3.10. Rational Functions; 3.11. Ideals; 3.12 ...