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{(x+3)/10x(2x-1)/4}=[(x+3)(2x-1)]/40.why not this{(x+3)/10x(2x-1)/4}=[4(x+3)]/40x[10(2x-1)]/40=(x+3)(2x-1),i'm confuse,what i'm doing wrong?

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  • {(x+3)/10x(2x-1)/4}=[(x+3)(2x-1)]/40.why not this{(x+3)/10x(2x-1)/4}=[4(x+3)]/40x[10(2x-1)]/40=(x+3)(2x-1),i'm confuse,what i'm doing wrong?


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